Jan 20, 2022 · Python sqrt limit for very large numbers? square root of a number greater than 10^2000 in Python 3 Which is faster in Python: x**.5 or math.sqrt (x)? Why does Python give the "wrong" …

Mar 13, 2013 · Is there an integer square root somewhere in python, or in standard libraries? I want it to be exact (i.e. return an integer), and raise an exception if the input isn't a perfect square. I tried u...

Jun 15, 2010 · I want to find the square root of a number without using the math module,as i need to call the function some 20k times and dont want to slow down the execution by linking to the math module …

There is. It's just ** =) Any nth root is an exponentiation by 1/n, so to get the square root of 9, you use 9**(1/2) (or 9**0.5) to get the cube root, you use 9 ** (1/3) (which we can't write with a simpler …

8 In python 2.6 the (float).__pow__() function uses the C pow() function and the math.sqrt() functions uses the C sqrt() function. In glibc compiler the implementation of pow(x,y) is quite complex and it is …

How could I check if a number is a perfect square? Speed is of no concern, for now, just working. See also: Integer square root in python.

Jan 31, 2015 · y = 10 * sqrt(70.707e2) A few notes: Python handles ridiculously large integer numbers without problems. For floating point numbers, it uses standard (C) conventions, and limits itself to 64 …

Jun 28, 2018 · I am looking for the more efficient and shortest way of performing the square root of a sum of squares of two or more numbers. I am actually using numpy and this code: np.sqrt(i**2+j**2) …

Dec 19, 2014 · Sympy Simplification with Square Root Asked 11 years, 1 month ago Modified 6 years, 8 months ago Viewed 16k times

Jan 4, 2015 · Here's my code: import cmath root = (cmath.sqrt(25)) print (root) raw_input() The problem i face is the result of root is 5+0j which is undesirable i only want the square root. How can i fix this?