The inductive effect is the effect on electron density in one portion of a molecule caused by electron-withdrawing or electron-donating groups elsewhere in the molecule. In a covalent bond between two …

The effect of strong base on water is to dramatically increase the concentration of OH^- ions and decrease the concentration of H_3O^+ ions. Water always contains at least small concentrations of …

Similarly, OH^- becomes H_2O, indicating a gain of a H^+ ion. So, you can say that NH_4^+ is the acid, and OH^- is the base. Conjugates are basically the "other" term. For every acid, you have a …

H^+ + OH^--> H_2O when the acid was added to the resulting solution. The H^+ and OH^- react in a 1:1 ratio. This tells us that the number of moles of H^+ used will be equal to the number of OH^- moles in …

The acid in excess is then titrated with N aOH (aq) of KNOWN concentration....we can thus get back to the concentration or molar quantity of M (OH)2...as it stands the question (and answer) are …

OH− (aq) + H3O+ (aq) → 2H2O(l) so you can say that when you mix these two solutions, the hydronium cations present in the hydrochloric acid solution will be the limiting reagent, i.e. they will be …

Strong Base collection => Group IA and Group IIA Hydroxides (Except for Beryllium Hydroxide) can be titrated with strong acid such that concentration of Alkali-Hydroxide = concentration of Hydroxide ion …

Explanation: < Since the molarity of either acid is the same, the moles of each acid are equal. That means the difference between their pH is determined solely on which acid dissociates more. Since …

The sulfate (VI) ion SO_4^(2-) is the only spectator in this reaction. The solubility of cobalt (III) hydroxide is only about 10^(-10) g/l so can be considered to be insoluble. We need a balanced equation so the …

Here's what I get. The general equation for the dissociation of a carboxylic acid is "R-COOH + H"_2"O" ⇌ "R-COO"^"-" + "H"_3"O"^+ All we have to do is write the ...