
What is a continuous extension? - Mathematics Stack Exchange
To find examples and explanations on the internet at the elementary calculus level, try googling the phrase "continuous extension" (or variations of it, such as "extension by continuity") …
Proof of Continuous compounding formula - Mathematics Stack …
Following is the formula to calculate continuous compounding A = P e^(RT) Continuous Compound Interest Formula where, P = principal amount (initial investment) r = annual interest …
Difference between continuity and uniform continuity
Jan 27, 2014 · To understand the difference between continuity and uniform continuity, it is useful to think of a particular example of a function that's continuous on $\mathbb R$ but not …
What's the difference between continuous and piecewise …
Oct 15, 2016 · A continuous function is a function where the limit exists everywhere, and the function at those points is defined to be the same as the limit. I was looking at the image of a …
Continuous bijection between compact and Hausdorff spaces is a ...
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The definition of continuous function in topology
21 I am self-studying general topology, and I am curious about the definition of the continuous function. I know that the definition derives from calculus, but why do we define it like that?I …
calculus - Are functions considered continuous at endpoints ...
In either case, a function is continuous on its domain if it is continuous at every point in the domain. Thus a function can be continuous on either $ [a,b]$ or $ (a,b)$.
is bounded linear operator necessarily continuous?
3 This property is unrelated to the completeness of the domain or range, but instead only to the linear nature of the operator. Yes, a linear operator (between normed spaces) is bounded if …
Continuous function proof by definition - Mathematics Stack …
Continuous function proof by definition Ask Question Asked 12 years, 7 months ago Modified 6 years, 5 months ago
real analysis - Continuous image of compact sets are compact ...
The fact that f is continuous doesn't guarantee that the image of f's inverse is open, much less is even defined. For example, f (x) = 1 is continuous but it's inverse isn't even defined. Maybe the …