Mar 12, 2017 · √6x − 5+10 −10 = 3 −10 ⇒ √6x −5 = −7 square both sides (√6x − 5)2 = (− 7)2 ⇒ 6x − 5 = 49 add 5 to both sides. 6x−5 +5 = 49+ 5 ⇒ 6x = 54 divide both sides by 6 6x 6 = 54 6 ⇒ …

Dec 17, 2017 · Explanation: #"differentiate using the "color (blue)"product rule"# #"given "f (x)=g (x)h (x)" then"# #f' (x)=g (x)h' (x)+h (x)g' (x)larrcolor (blue)"product rule"# #g (x)=6x^2rArrg' …

How do you write a verbal expression for the algebraic expression #4 (2x-7)#? What is the numerical coefficient of the variable and the constant term of 6x + 5? What is the difference …

Explanation: The denominator #x^2-6x+8# can be factored in the form # (x-2) (x-4)#. So, we try the partial fraction expansion of the form # (17x-50)/ (x^ (2)-6x+8) = A/ (x-2)+B/ (x-4)# …

How do you use the important points to sketch the graph of y = x2 − 6x + 1? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs

Explanation: The problem #int (2x)/ (x^2+6x+13)dx# can be solved By the method as shown below. Let #u=x^2+6x+13#, #du= (2x+6)dx# Further, in the numerator, we have only …

Measure of angle LhatOM = 48^0 7x-92+6x+12=180 1) Combine like terms 7x - 92 + 6x + 12 =180 13x - 80= 180 2) Add color (blue) (80) to both sides (13x) - cancel80 color (blue) (+ …

Aug 1, 2015 · Explanation: In order to solve this quadratic equation by completing the square, you need to write the left side of the equation as the square of a binomial.

0, 1, 3 To solve this, we set the equation equal to 0 and factor it. First, we can factor out 6x to get 6x(x^2-4x+3)=0. Next we can factor out the area in parentheses. To do this, we need to find …

Explanation: Given: #x^2+9y^2+6x-90y+225=0# Subtract 225 from both sides: #x^2+9y^2+6x-90y=-225# We are going to complete the square for #x^2+6x+ h^2= (x -h)^2#, therefore, we …